How to enable disable generate picking list button based on condition

(0) Share

Report

Posted on by Sona Jee

Hi experts,

I want to enable disable generate picking list button based on some condition.

I have tried below code:

[FormDataSourceEventHandler(formDataSourceStr(SalesTable, SalesTable), FormDataSourceEventType::Activated)]
    public static void SalesTable_OnActivated(FormDataSource sender, FormDataSourceEventArgs e)
    {
        SalesTable      salesTable                  = sender.cursor();
        FormDataSource  salesTable_ds               = sender.formRun().dataSource("SalesTable");
        FormRun         element                     = sender.formRun();
        FormControl     buttonUpdatePickingList     = element.design(0).controlName("buttonUpdatePickingList");
       
        if(condition)
        {
            buttonUpdatePickingList.enabled(false);            
        }
        else
        {
            buttonUpdatePickingList.enabled(true);
        }

Please suggest the right way

Thank you

Sona Jee

I have the same question (0)

All responses (5)

Answers (1)

Verified answer

Sona Jee on at

Like (0)

Report
RE: How to enable disable generate picking list button based on condition

Hi All,

I did like this,its worked

[ExtensionOf(classStr(SalesTableFormJournalButtonState))] final class SalesTables_Extension { ///
/// ///
public void applyState() { SalesTable salestable = this.parmFormRun().dataSource(tableStr(SalesTable)).cursor(); next applyState(); switch (this.parmFormRun().name()) { case formStr(SalesTable): CustTable custTable = CustTable::find(salesTable.CustAccount); if(custTable.Approval == NoYes::Yes) { this.enableButton(formControlStr(SalesTable, buttonUpdatePickingList), false); this.enableButton(formControlStr(SalesTable, buttonUpdatePackingSlip), false); } else { this.enableButton(formControlStr(SalesTable, buttonUpdatePickingList), true); this.enableButton(formControlStr(SalesTable, buttonUpdatePackingSlip), true); } } } }

Thank you

Sona Jee

Was this reply helpful? Yes No
WillWU 22,359 on at

Like (0)

Report

RE: How to enable disable generate picking list button based on condition

Hi Sona,

Please try to code in the OnInitialized event handler of the form.

[FormEventHandler(formStr(SalesTable), FormEventType::Initialized)]
public static void SalesTable_OnInitialized(xFormRun sender, FormEventArgs e)
{
FormDataSource salesTable_ds = sender.dataSource(formDataSourceStr(SalesTable,SalesTable)) as FormDataSource;
SalesTable salesTable= salesTable_ds.cursor();

}

Was this reply helpful? Yes No
André Arnaud de Cal... 296,568 Super User 2025 Season 2 on at

Like (0)

Report

RE: How to enable disable generate picking list button based on condition

Hi Sona,

This button is also updated by some other logic from standard Dynamics 365. Check where this coding is exactly and see if you can extend that method instead of this data source event.

Was this reply helpful? Yes No
Sona Jee on at

Like (0)

Report
RE: How to enable disable generate picking list button based on condition

Hi Andre,

Thanks for the response

My condition is that when we create sales order for that particular customer account we have added on checkbox in master like this:

If this checkbox is set to yes then this generate picking list button will be disable.

And my current code showing no results.

[FormDataSourceEventHandler(formDataSourceStr(SalesTable, SalesTable), FormDataSourceEventType::Activated)] public static void SalesTable_OnActivated(FormDataSource sender, FormDataSourceEventArgs e) { SalesTable salesTable = sender.cursor(); FormDataSource salesTable_ds = sender.formRun().dataSource("SalesTable"); FormRun element = sender.formRun(); FormControl buttonUpdatePickingList = element.design(0).controlName("buttonUpdatePickingList"); CustTable custTable = CustTable::find(salesTable.CustAccount); if(custTable.Approval == NoYes::Yes) { buttonUpdatePickingList.enabled(false); } else { buttonUpdatePickingList.enabled(true); }

When i debugged its going in the condition but not disabling the button.

So please help me how to do.

Thank you

Sona Jee

Was this reply helpful? Yes No
André Arnaud de Cal... 296,568 Super User 2025 Season 2 on at

Like (0)

Report

RE: How to enable disable generate picking list button based on condition

Hi Sona,

What is your exact condition and where exactly do you need help? Did you test your coding? What is the current result of this?

Was this reply helpful? Yes No